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Decimal expansions · 2 marks

A rational number in its lowest form has denominator 23 × 5. How many decimal places will its decimal expansion have? Explain your answer.

Answer: 3 decimal places. p23 × 5 = 25p103, and because p is odd and not a multiple of 5 (lowest form), 25p ends in 5, so the third decimal digit is non-zero.

Step-by-step solution

Idea: Make the denominator a power of 10 by supplying the missing 5s: the highest power among 23 and 51 is 3, so we need 103. Then check the last digit is not 0.

  1. Let the number be p23 × 5 in lowest form. Multiply top and bottom by 52: 25p23 × 53 = 25p1000, so the decimal has at most 3 places.1 mark
  2. Lowest form means p has no factor 2 or 5, so p is odd. Then 25p is an odd multiple of 25, which ends in 25 or 75; its last digit is 5, not 0. So the third decimal place is non-zero: exactly 3 decimal places. (E.g. 140 = 0.025, 340 = 0.075.)1 mark
Exactly 3 decimal places, since p/(2³ × 5) = 25p/10³ and 25p ends in 5.

Check: 740 = 0.175, 1140 = 0.275, 3940 = 0.975: each has 3 places ✓.

Answer to write in the exam

p23 × 5 = p × 5223 × 53 = 25p103

Lowest form ⇒ p odd, 5 ∤ p ⇒ 25p ends in 5

∴ Exactly 3 decimal places (e.g. 340 = 0.075)

Common mistakes that cost marks

  • Adding the powers (3 + 1 = 4) and answering 4 places. The number of places is the larger power, 3.
  • Answering 1 place by looking at the single 5.
  • Not explaining why the last digit cannot be 0 (it needs the lowest-form condition).

How this can come in the exam

MCQ (1 mark)

A rational number in lowest form has denominator 22 × 54. Its decimal expansion terminates after

  1. 2 places
  2. 4 places
  3. 6 places
  4. 8 places
Show answer

(B) 4 places
Multiply by 22 to get 104: 4 places.

Short answer (2 marks)

Write 980 as a decimal by making the denominator a power of 10. How many decimal places does it have?

Show answer80 = 24 × 5, so multiply by 53 = 125: 112510000 (1 mark) = 0.1125, 4 decimal places (1 mark).

Try one yourself

How many decimal places does a lowest-form rational number with denominator 2 × 53 have?

Show answer

3 places: p250 = 4p1000, and 4p does not end in 0 since 5 ∤ p.

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