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Volume of a cylinder and a sphere · 3 marks

A cylindrical glass of height 25 cm and radius 4 cm has water up to a height of 16 cm. A crow wants to drink water from this glass. The water must be at a height of 20 cm for the crow to reach it. There are some marbles lying around. How many marbles of radius 1 cm should the crow drop into the glass to make the water reach the required height?

Answer: The water must rise 4 cm: π × 42 × 4 = 64π cm3. One marble = 43π cm3. Number = 64π ÷ 43π = 48 marbles.

Step-by-step solution

Given: Glass: radius 4 cm, height 25 cm, water at 16 cm; Needed: water at 20 cm; Marbles: radius 1 cm
To find: Number of marbles

Idea: Each sunken marble pushes up water equal to its own volume. The rise needed is a cylinder of water 4 cm tall.

  1. Rise needed = 20 − 16 = 4 cm. Volume to be displaced = π × 42 × 4 = 64π cm3.1 mark
  2. Volume of one marble = 43π × 13 = 43π cm3.1 mark
  3. Number = 64π ÷ 43π = 64 × 34 = 48 marbles. (The glass is 25 cm tall, so the water does not overflow.)1 mark
48 marbles.

Check: 48 marbles × 43π = 64π = π × 16 × 4 ✓.

Answer to write in the exam

Rise = 20 − 16 = 4 cm

Volume to displace = π × 42 × 4 = 64π cm3

One marble = 43π × 13 = 43π cm3

∴ Number = 64π ÷ 43π = 48

Common mistakes that cost marks

  • Using the whole height 20 cm (or 16 cm) instead of the rise of 4 cm.
  • Using surface area 4πr2 for the marble instead of volume.

How this can come in the exam

MCQ (1 mark)

Marbles of radius 1.5 cm are dropped into a cylindrical jar of radius 3 cm. How many raise the water by 2 cm?

  1. 2
  2. 4
  3. 6
  4. 8
Show answer

(B) 4
π × 32 × 2 = 18π; one marble = 43π × 1.53 = 4.5π; 18π ÷ 4.5π = 4.

Try one yourself

How many spherical lead shots of radius 0.5 cm must be dropped into a cylindrical beaker of radius 5 cm to raise the water by 2 cm?

Show answer

π × 25 × 2 = 50π; one shot 43π × 0.125 = π6; 50π ÷ π6 = 300 shots.

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