A circle has a radius of 15 cm. A chord is drawn. The distance from the centre of the circle to the chord is 9 cm. What is the length of the chord?
Step-by-step solution
To find: Length of the chord AB
Idea: Chord length = 2√(r2 − d2): the perpendicular from the centre bisects the chord and forms a right triangle with the radius.
- OM ⟂ AB, so M is the midpoint of AB and AB = 2MB.½ mark
- MB2 = OB2 − OM2 = 225 − 81 = 144, so MB = 12 cm.1 mark
- AB = 2 × 12 = 24 cm.½ mark
Check: 92 + 122 = 81 + 144 = 225 = 152 ✓.
Answer to write in the exam
OB = 15 cm, OM = 9 cm, OM ⟂ AB
MB2 = OB2 − OM2 = 225 − 81 = 144 ⇒ MB = 12 cm
AB = 2MB (perpendicular from the centre bisects the chord)
∴ AB = 24 cm
Common mistakes that cost marks
- Stopping at 12 cm (half the chord).
- Writing 15 − 9 = 6 and doubling to 12 cm: lengths cannot be subtracted like that; use squares.
- Squaring wrongly: 152 = 225, 92 = 81.
How this can come in the exam
The length of a chord which is 6.5 cm from the centre of a circle of radius 9.7 cm is
- 7.2 cm
- 14.4 cm
- 3.2 cm
- 16.2 cm
Show answer
(B) 14.4 cm
Half-chord = √(9.72 − 6.52) = √(94.09 − 42.25) = √51.84 = 7.2 cm; chord = 2 × 7.2 = 14.4 cm.
Try one yourself
A chord is 21 cm from the centre of a circle of radius 35 cm. Find its length.
Show answer
Half-chord = √(1225 − 441) = √784 = 28 cm, so the chord is 56 cm.
More questions like this
- Prove that the perpendicular bisector of a chord passes through the centre of the circle.
- The diameter of a circle is AB. Point C is on the circumference. What is the measure of the ∠ACB? Explain your reasoning.
- ABCD is a cyclic quadrilateral inscribed in a circle. If ∠A measures 75°, what is the measure of ∠C? If ∠B measures 110°, what is the measure of ∠D?
- Quadrilateral PQRS is inscribed in a circle. If ∠P = (2x + 10)° and ∠R = (3x − 20)°, find the value of x and the measures of ∠P and ∠R.
- The distance of a chord of length 16 cm from the centre of a circle is 6 cm. Find the radius of the circle.