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Linear equations · 2 marks

A chess club charges a joining fee of ₹200 plus ₹50 for every match played. If a player paid ₹750, how many matches did he play?

Answer: 200 + 50m = 750 gives m = 11. He played 11 matches.

Step-by-step solution

Given: Amount for m matches = ₹(200 + 50m); Amount paid = ₹750
To find: The number of matches m

Idea: Set the linear polynomial equal to the amount paid. This gives a linear equation; solve it for m.

  1. 200 + 50m = 750½ mark
  2. Take away the joining fee: 50m = 750 − 200 = 550.½ mark
  3. m = 550 ÷ 50 = 11.½ mark
  4. So he played 11 matches.½ mark
He played 11 matches.

Check: 200 + 50 × 11 = 200 + 550 = 750 ✓.

Answer to write in the exam

200 + 50m = 750

50m = 550

m = 11

∴ He played 11 matches

Common mistakes that cost marks

  • Dividing 750 by 50 directly to get 15. The ₹200 joining fee must be taken away first.
  • Adding 200 instead of subtracting: 50m = 950.
  • Stopping at 50m = 550 and giving 550 as the answer.

How this can come in the exam

MCQ (1 mark)

A library charges ₹150 membership and ₹10 per book borrowed. Ravi paid ₹290. How many books did he borrow?

  1. 29
  2. 14
  3. 15
  4. 44
Show answer

(B) 14
150 + 10b = 290, so 10b = 140 and b = 14.

Short answer (2 marks)

A coaching centre charges ₹1200 admission and ₹800 per month. A student has paid ₹8400 in total. For how many months has she studied?

Show answer1200 + 800n = 8400 (½ mark), 800n = 7200 (1 mark), n = 9 months (½ mark).

Try one yourself

Using the same chess club charges, how many matches did a player play if he paid ₹1200?

Show answer

200 + 50m = 1200, so 50m = 1000 and m = 20 matches.

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