A chess club charges a joining fee of ₹200 plus ₹50 for every match played. If a player paid ₹750, how many matches did he play?
Answer: 200 + 50m = 750 gives m = 11. He played 11 matches.
Step-by-step solution
Given: Amount for m matches = ₹(200 + 50m); Amount paid = ₹750
To find: The number of matches m
To find: The number of matches m
Idea: Set the linear polynomial equal to the amount paid. This gives a linear equation; solve it for m.
- 200 + 50m = 750½ mark
- Take away the joining fee: 50m = 750 − 200 = 550.½ mark
- m = 550 ÷ 50 = 11.½ mark
- So he played 11 matches.½ mark
He played 11 matches.
Check: 200 + 50 × 11 = 200 + 550 = 750 ✓.
Answer to write in the exam
200 + 50m = 750
50m = 550
m = 11
∴ He played 11 matches
Common mistakes that cost marks
- Dividing 750 by 50 directly to get 15. The ₹200 joining fee must be taken away first.
- Adding 200 instead of subtracting: 50m = 950.
- Stopping at 50m = 550 and giving 550 as the answer.
How this can come in the exam
MCQ (1 mark)
A library charges ₹150 membership and ₹10 per book borrowed. Ravi paid ₹290. How many books did he borrow?
- 29
- 14
- 15
- 44
Show answer
(B) 14
150 + 10b = 290, so 10b = 140 and b = 14.
Short answer (2 marks)
A coaching centre charges ₹1200 admission and ₹800 per month. A student has paid ₹8400 in total. For how many months has she studied?
Show answer
1200 + 800n = 8400 (½ mark), 800n = 7200 (1 mark), n = 9 months (½ mark).Try one yourself
Using the same chess club charges, how many matches did a player play if he paid ₹1200?
Show answer
200 + 50m = 1200, so 50m = 1000 and m = 20 matches.
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